The work performed by a gas is 507 J when it expands from 56.3 L to 58.8 L against an external pressure of 2.0 atm.

Question

Quizplus · Accepted Answer

The work done by a gas is given by the formula W = -PΔV, where P is the external pressure and ΔV is the change in volume. In this case, the external pressure is 2.0 atm and the change in volume is 58.8 L - 56.3 L = 2.5 L. Therefore, the work done by the gas is W = -2.0 atm * 2.5 L = -5.0 J.

The Work Performed by a Gas Is 507 J When