The heat involved when 150.0 g of Fe increases its temperature from 300.°C to 350.°C is 3370 J. The specific heat of Fe is 0.449 J/g·°C.

Question

Quizplus · Accepted Answer

The heat involved in raising the temperature of an object is given by the equation Q = mcΔT, where Q is the heat, m is the mass, c is the specific heat, and ΔT is the change in temperature. In this case, Q = 3370 J, m = 150.0 g, c = 0.449 J/g·°C, and ΔT = 350.°C - 300.°C = 50.°C. Substituting these values into the equation gives Q = (150.0 g)(0.449 J/g·°C)(50.°C) = 3370 J. Therefore, the heat involved in raising the temperature of 150.0 g of Fe from 300.°C to 350.°C is 3370 J, which is consistent with the given value.

The Heat Involved When 150