Given the thermochemical equation.
N₂+ 2O₂ → 2NO₂ ∆H = -114.1 kJ
The enthalpy of formation of NO ₂ is -114.1 kJ.

Question

Given the thermochemical equation. N₂+ 2O₂ → 2NO₂ ∆H = -114.1 kJ The enthalpy of formation of NO ₂ is -114.1 kJ.

Quizplus · Accepted Answer

The given thermochemical equation shows the reaction of N₂ and O₂ to form 2NO, with a ΔH of -114.1 kJ. The enthalpy change given is for the formation of 2 moles of NO, not per mole. The enthalpy of formation of NO (per mole) would be -114.1 kJ / 2 = -57.05 kJ/mol.

Given the Thermochemical Equation