Given the thermochemical equation 2C(s) + 2O₂(g) → 2CO₂(g) ΔH = −787 kJ
What is the ΔH for the reaction CO₂(g) → C(s) + O₂(g) ?

Question

Given the thermochemical equation 2C(s) + 2O₂(g) → 2CO₂(g) ΔH = −787 kJ What is the ΔH for the reaction CO₂(g) → C(s) + O₂(g)?

Quizplus · Accepted Answer

To find the ΔH for the reverse reaction, you simply reverse the sign of the given ΔH. Since the given ΔH for the forward reaction is −787 kJ for 2 moles of CO₂(g), reversing the reaction and dividing by 2 (to get the ΔH for 1 mole) gives +394 kJ.

Given the Thermochemical Equation 2C(s) + 2O2(g) → 2CO2(g) ΔH

Given the Thermochemical Equation 2C(s) + 2O₂(g) → 2CO₂(g) ΔH