For 2Na + Cl₂ → 2NaCl ΔH is −772 kJ. What is the ΔH for the reaction NaCl → Na + ½Cl₂?

Question

Quizplus · Accepted Answer

The ΔH for the reverse reaction is the negative of the ΔH for the forward reaction. Since the forward reaction releases 772 kJ (ΔH = −772 kJ), the reverse reaction requires the absorption of the same amount of energy, but since the coefficients are halved (forming only 1 NaCl instead of 2), the energy change is also halved. Therefore, ΔH = +386 kJ.

For 2Na + Cl2 → 2NaCl ΔH Is −772 KJ

For 2Na + Cl₂ → 2NaCl ΔH Is −772 KJ