Consider the chemical reaction, 2Al + 3Cl₂ $\rightarrow$ 2AlCl₃. Here, 212.7 g of chlorine can produce a maximum of 266.66 g of AlCl₃ (Molar masses: Al = 26.98 g; Cl = 35.45 g).

Question

Quizplus · Accepted Answer

The given statement is true because the balanced chemical equation shows that 2 moles of Al react with 3 moles of Cl₂ to produce 2 moles of AlCl₃. Therefore, 212.7 g of chlorine (3 moles) can react with 266.66 g of Al (2 moles) to produce 266.66 g of AlCl₃ (2 moles).

Consider the Chemical Reaction, 2Al + 3Cl2 →\rightarrow→ 2AlCl3

Consider the Chemical Reaction, 2Al + 3Cl₂ $\rightarrow$ 2AlCl₃