Consider the unbalanced chemical reaction Al + Cl₂ $\rightarrow$ AlCl₃. How many moles of AlCl₃ can be obtained from 360 grams of Cl₂? (Molar masses: Cl = 35.45 g/mol, Al = 26.98 g/mol)

Question

Quizplus · Accepted Answer

First, correct the chemical equation: $2Al + 3Cl_2 \rightarrow 2AlCl_3$. To find moles of $Cl_2$ from 360 g, use its molar mass (70.9 g/mol): $360 \, \text{g} / 70.9 \, \text{g/mol} = 5.08 \, \text{moles of} \, Cl_2$. According to the balanced equation, 3 moles of $Cl_2$ produce 2 moles of $AlCl_3$, so $5.08 \, \text{moles of} \, Cl_2$ will produce $(5.08 \, \text{moles} \times 2 \, \text{moles of} \, AlCl_3) / 3 = 3.39 \, \text{moles of} \, AlCl_3$. The molar mass of $AlCl_3$ is $133.34 \, \text{g/mol}$, so $3.39 \, \text{moles} \times 133.34 \, \text{g/mol} = 451.8 \, \text{g}$, which rounds to 450 g when not considering significant figures.

Consider the Unbalanced Chemical Reaction Al + Cl2 →\rightarrow→ AlCl3

Consider the Unbalanced Chemical Reaction Al + Cl₂ $\rightarrow$ AlCl₃