Consider the equation, 2Rb + MgCl₂ $\rightarrow$ Mg + 2RbCl. If 82.00 g of Rb are available, what is the amount of MgCl₂ needed? (Molar masses: Rb = 85.47 g; Mg = 24.3 g; Cl = 35.45 g)

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The Answer of Consider the equation, 2Rb + MgCl₂ $\rightarrow$ Mg + 2RbCl. If 82.00 g of Rb are available, what is the amount of MgCl₂ needed? (Molar masses: Rb = 85.47 g; Mg = 24.3 g; Cl = 35.45 g)

Consider the Equation, 2Rb + MgCl2 →\rightarrow→ Mg + 2RbCl

Consider the Equation, 2Rb + MgCl₂ $\rightarrow$ Mg + 2RbCl