The half-life of americium-241 is 432 y. If 2.00 g of americium-241 is present in a sample, what mass of americium-241 is present after 1,000.0 y?

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Quizplus · Accepted Answer

The half-life formula is used to calculate the remaining mass: $ N = N_0 \times (1/2)^{t/T} $. Here, $ N_0 = 2.00 $ g, $ t = 1000.0 $ y, and $ T = 432 $ y. Calculating gives $ N = 2.00 \times (1/2)^{1000/432} \approx 0.402 $ g.

The Half-Life of Americium-241 Is 432 Y