Given: 6H++ 2MnO4− + 5H2O2 → 2Mn+2 + 5O2 + 8H2O
Identify what is being oxidized and reduced in this redox reaction.
A) Oxidation numbers of all the atoms remain the same.
B) H is being oxidized from +6 to +8; Mn stays the same.
C) O is being oxidized from -1 to 0; Mn is being reduced from +7 to +2.
D) Mn is being oxidized from -4 to -2; O is being reduced from +6 to +5.
E) H is being oxidized from +6 to +5; Mn is being reduced from +1 to -2.
Correct Answer:
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