The freezing point of a 1.9 m solution of NaCl in H₂O is -3.5°C if K_f = 1.86°C/m.

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Quizplus · Accepted Answer

The freezing point depression is given by the equation:$$\Delta T_f = K_f \times m$$where:* $\Delta T_f$ is the freezing point depression* $K_f$ is the freezing point depression constant* $m$ is the molality of the solutionIn this case, we have:* $\Delta T_f = -3.5°C$* $K_f = 1.86°C/m$* $m = 1.9 m$Substituting these values into the equation, we get:$$-3.5°C = 1.86°C/m \times 1.9 m$$$$-3.5°C = 3.534°C$$This equation is true, so the freezing point of the solution is -3.5°C.

The Freezing Point of a 1