A shot-putter moves his arm and the 7.0-kg shot through a distance of 1.0 m,giving the shot a velocity of 10 m/s from rest.Find the average force exerted on the shot during this time.
A)175 N
B)350 N
C)525 N
D)700 N

Question

Quizplus · Accepted Answer

The work-energy principle states that the work done on an object is equal to the change in its kinetic energy. The kinetic energy of the shot is (1/2)mv^2 = (1/2)(7 kg)(10 m/s)^2 = 350 J. Since the work done is also equal to force times distance (W = Fd), we have F = W/d = 350 J / 1 m = 350 N.

A Shot-Putter Moves His Arm and the 7