Wiley Coyote has missed the elusive road runner once again.This time,he leaves the edge of the cliff at 50.0 m/s horizontal velocity.If the canyon is 100 m deep,how far from his starting point at the edge of the cliff does the coyote land?
A)226 m
B)247 m
C)339 m
D)400 m

Question

Quizplus · Accepted Answer

The correct answer is A because the horizontal velocity is constant, so the horizontal displacement is simply the velocity multiplied by the time it takes to fall 100 m. The time it takes to fall 100 m is given by:```t = sqrt(2 * h / g) = sqrt(2 * 100 m / 9.8 m/s^2) = 4.52 s```Therefore, the horizontal displacement is:```d = v * t = 50.0 m/s * 4.52 s = 226 m```

Wiley Coyote Has Missed the Elusive Road Runner Once Again