The Paschen series of hydrogen corresponds to electron transitions from higher levels to n = 3.What is the shortest wavelength in that series? (R = 1.097 x 10⁷ m^-1 and 1 nm = 10^-9 m) A)365 nm B)820 nm C)1 094 nm D)313 nm

Question

Quizplus · Accepted Answer

The shortest wavelength in the Paschen series corresponds to the transition from n = ∞ to n = 3. Using the Rydberg formula: 1/λ = R(1/3² - 1/∞²), we find λ = 1/(R/9) = 9/R. Substituting R = 1.097 x 10^7 m^-1, λ = 9/(1.097 x 10^7) = 820 nm.

The Paschen Series of Hydrogen Corresponds to Electron Transitions from Higher