The red light from a HeNe laboratory laser results from a transition in Ne.Determine the wavelength of the light given off if the energy difference between states is 1.96 eV.(h = 6.63 x 10^-34J*s,c = 3.00 x 10⁸ m/s,1 eV = 1.60 x 10^-19 J,and 1 nm = 10^-9 m) A)575 nm B)601 nm C)634 nm D)652 nm

Question

Quizplus · Accepted Answer

We can use the formula for energy of a photon: 
E = hc/λ 
where E is the energy difference between the states, h is Planck's constant, c is the speed of light, and λ is the wavelength. 
Plugging in the given values, we get: 
1.96 eV = (6.63 x 10^-34 J s)(3.00 x 10^8 m/s)/λ 
Solving for λ, we get: 
λ = (6.63 x 10^-34 J s)(3.00 x 10^8 m/s)/(1.96 eV)(1.60 x 10^-19 J/eV) 
λ = 634 nm 
Therefore, the wavelength of the red light from the HeNe laser is 634 nm.

The Red Light from a HeNe Laboratory Laser Results from a Transition