Light of wavelength 480 nm is incident on a metallic surface with a resultant photoelectric stopping potential of 0.55 V.What is the work function of the metal? (h = 6.63 x 10^-34 J*s,c = 3.00 x 10⁸ m/s,1 eV = 1.60 x 10^-19 J,and 1 nm = 10^-9m)

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Explanation:The work function of the metal is given by:$$W = h
u - eVs$$where:* h is Planck's constant* $
u$ is the frequency of the light* e is the charge of an electron* Vs is the stopping potentialSubstituting the given values, we get:$$W = (6.63 	imes 10^{-34} 	ext{ J s})(3 	imes 10^8 	ext{ m/s}) / (480 	imes 10^{-9} 	ext{ m}) - (1.60 	imes 10^{-19} 	ext{ J})(0.55 	ext{ V})$$$$W = 4.14 	imes 10^{-19} 	ext{ J} - 8.80 	imes 10^{-20} 	ext{ J}$$$$W = 3.26 	imes 10^{-19} 	ext{ J}$$Converting to electron volts, we get:$$W = (3.26 	imes 10^{-19} 	ext{ J}) / (1.60 	imes 10^{-19} 	ext{ J/eV})$$$$W = 2.04 	ext{ eV}$$Therefore, the work function of the metal is 2.04 eV.

Light of Wavelength 480 Nm Is Incident on a Metallic