The spacing between atoms in KCl crystal is 3.1 x 10^-10m.At what angle from the surface will a beam of 3.14 x 10^-11m x-rays be constructively scattered? A)57 $\degree$ B)2.9 $\degree$ C)90 $\degree$ D)10 $\degree$

Question

Quizplus · Accepted Answer

The Bragg's law states that constructive interference occurs when 2dsinθ = nλ, where d is the spacing between the atoms, θ is the angle of incidence, λ is the wavelength of the X-ray, and n is an integer. Rearranging this equation, we get sinθ = nλ/2d. Plugging in the given values, we get sinθ = (1λ/2 x 3.1 x 10^-10m). Solving for θ, we get θ = 2.9°. Therefore, the beam of X-rays will be constructively scattered at an angle of 2.9° from the surface, which corresponds to choice B.

The Spacing Between Atoms in KCl Crystal Is 3 °\degree° B)29 °\degree°

The Spacing Between Atoms in KCl Crystal Is 3 $\degree$ B)29 $\degree$