If the measured momentum of an electron is 3.20 x 10^-27 kg*m/s with an uncertainty of 1.6 x 10^-29kg*m/s,what is the minimum uncertainty in the position? (h = 6.63 x 10^-34 J*s) A)2.6 x 10^-8m B)3.3 x 10^-6 m C)0.63 x 10^-4 m D)1.1 x 10^-3 m

Question

Quizplus · Accepted Answer

The uncertainty principle states that ΔxΔp ≥ h/4π. 
Using the given values, we can calculate the uncertainty in position:

Δp = 1.6 x 10^-29 kg·m/s 
p = 3.20 x 10^-27 kg·m/s

Δx ≥ h/(4πΔp) = 3.3 x 10^-6 m

Therefore, the minimum uncertainty in position is 3.3 x 10^-6 m, which corresponds to choice B.

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