A Young's interference experiment is conducted with blue-green argon laser light (l = 515 nm).The separation between the slits is 0.50 mm,and the interference pattern appears on a screen 3.3 m away.What is the spacing between the bright fringes? (1 nm = 10^-9 m) A)1.7 mm B)3.4 mm C)5.1 mm D)6.8 mm

Question

Quizplus · Accepted Answer

The spacing between the bright fringes is given by the formula:
d*sinθ = mλ
where d is the separation between the slits, θ is the angle between the central maximum and the mth bright fringe, λ is the wavelength of the light, and m is the order of the fringe (m = 0 for the central maximum).
We can rearrange this equation to get the spacing between the bright fringes:
D = (mλL)/d
where L is the distance from the slits to the screen.
Substituting the given values, we get:
D = (1*515*10^-9*3.3)/0.50 = 3.4 mm
Therefore, the spacing between the bright fringes is 3.4 mm. The best choice is B.

A Young's Interference Experiment Is Conducted with Blue-Green Argon Laser