How far above the horizon is the moon when its image reflected in calm water is completely polarized? (n_water = 1.333) A)53.12 $\degree$ B)18.44 $\degree$ C)22.20 $\degree$ D)36.88 $\degree$

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Quizplus · Accepted Answer

The angle of polarization (Brewster's angle) is given by tan(θ) = n, where n is the refractive index of water. Solving for θ gives θ = arctan(1.333), which is approximately 53.12°. The angle above the horizon is 90° - 53.12° = 36.88°.

How Far Above the Horizon Is the Moon When Its °\degree°

How Far Above the Horizon Is the Moon When Its $\degree$