An AC power generator produces 25 A (rms)at 3 600 V.The energy is transmitted through a long-distance power line,which has a total resistance of 100 W.What percentage of the power delivered by the generator is dissipated as heat in the long-distance line if a step-up transformer is not used?
A)0.09%
B)1.8%
C)32%
D)69%

Question

Quizplus · Accepted Answer

The power delivered by the generator can be calculated using the formula P = VI, where V is the voltage and I is the current. Therefore, P = (3600V)(25A) = 90,000W.

The power dissipated as heat in the long-distance line can be calculated using the formula P = I^2R, where R is the resistance of the line. Therefore, P = (25A)^2(100Ω) = 62,500W.

The percentage of power dissipated as heat in the line can be calculated as (power dissipated/power delivered)*100%. Thus, the percentage is (62,500W/90,000W)*100% = 69.4%, which rounds to 69%. Therefore, the answer is D, 69%.

An AC Power Generator Produces 25 a (Rms)at 3 600