A square coil,enclosing an area with sides 2.0 cm long,is wrapped with 2 500 turns of wire.A uniform magnetic field perpendicular to its plane is turned on and increases to 0.25 T during an interval of 1.0 s.What average voltage is induced in the coil?
A)0.25 V
B)0.12 V
C)2.0 V
D)2.5 V

Question

Quizplus · Accepted Answer

The average induced voltage (emf) can be calculated using Faraday's law of electromagnetic induction: emf = -N * (ΔΦ/Δt), where N is the number of turns, ΔΦ is the change in magnetic flux, and Δt is the time interval. The change in flux ΔΦ = B * A, where B is the magnetic field and A is the area. Here, A = (0.02 m)^2, B = 0.25 T, N = 2500, and Δt = 1 s. Substituting these values gives emf = 0.25 V.

A Square Coil,enclosing an Area with Sides 2