An inductor,battery,resistance,and ammeter and switch are connected in series.If the switch,initially open,is now closed,what is the current's final value?

Question

Quizplus · Accepted Answer

Once the switch is closed, current begins to flow in the circuit. As a result of the inductor’s self-induction property, the current builds up gradually. The rate at which the current builds up is determined by the time constant of the circuit, which is given by L/R, where L is the inductance of the inductor, and R is the resistance of the circuit. As time passes, the current approaches its steady-state value, which is equal to the battery voltage divided by the resistance of the circuit. Therefore, the final value of the current is given by I = V/R, where V is the battery voltage.

An Inductor,battery,resistance,and Ammeter and Switch Are Connected in Series