A 50-g ball traveling at 25.0 m/s is bounced off a brick wall and rebounds at 22.0 m/s.A high-speed camera records this event.If the ball is in contact with the wall for 3.50 ms,what is the average acceleration of the ball during this time interval? A)13 400 m/s² B)6 720 m/s² C)857 m/s² D)20 m/s²

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Quizplus · Accepted Answer

The average acceleration can be calculated using the formula: a = (v_f - v_i) / Δt. Here, v_f = -22.0 m/s (since it rebounds in the opposite direction), v_i = 25.0 m/s, and Δt = 3.50 ms = 0.0035 s. So, a = (-22.0 - 25.0) / 0.0035 = -13,400 m/s².

A 50-G Ball Traveling at 25