A ball is pushed with an initial velocity of 4.0 m/s.The ball rolls down a hill with a constant acceleration of 1.6 m/s².The ball reaches the bottom of the hill in 8.0 s.What is the ball's velocity at the bottom of the hill? A)10 m/s B)12 m/s C)16 m/s D)17 m/s

Question

Quizplus · Accepted Answer

The ball's velocity at the bottom of the hill can be found using the equation:v = u + atwhere:v is the final velocityu is the initial velocitya is the accelerationt is the timeSubstituting the given values into the equation, we get:v = 4.0 m/s + (1.6 m/s^2)(8.0 s)v = 4.0 m/s + 12.8 m/sv = 16.8 m/sTherefore, the ball's velocity at the bottom of the hill is 16.8 m/s, which is closest to choice D) 17 m/s.

A Ball Is Pushed with an Initial Velocity of 4