An automobile driver puts on the brakes and decelerates from 30.0 m/s to zero in 10.0 s.What distance does the car travel?
A)150 m
B)196 m
C)336 m
D)392 m

Question

Quizplus · Accepted Answer

The car decelerates uniformly, so we can use the formula for distance: $ d = \frac{(v_i + v_f)}{2} \times t $, where $ v_i = 30.0 \, \text{m/s} $, $ v_f = 0 \, \text{m/s} $, and $ t = 10.0 \, \text{s} $. Plugging in the values, $ d = \frac{(30.0 + 0)}{2} \times 10.0 = 150 \, \text{m} $.

An Automobile Driver Puts on the Brakes and Decelerates from 30.0