A Cessna aircraft has a lift-off speed of 120 km/hr.What minimum constant acceleration does this require if the aircraft is to be airborne after a take-off run of 240 m? A)2.31 m/s² B)3.63 m/s² C)4.63 m/s² D)5.55 m/s²

Question

Quizplus · Accepted Answer

First, we need to convert the lift-off speed from km/hr to m/s.

120 km/hr = 33.33 m/s

Using the kinematic equation:

vf^2 = vi^2 + 2ad

where vf = final velocity, vi = initial velocity, a = acceleration, and d = distance

We can solve for the minimum constant acceleration, a:

a = (vf^2 - vi^2)/2d

a = (0 - 33.33^2)/(2*240)

a = -111.11/480

a = -0.23 m/s^2

However, we need a positive acceleration for the aircraft to take off. So, we take the absolute value:

a = 0.23 m/s^2

Therefore, the minimum constant acceleration required for the aircraft to become airborne is 0.23 m/s^2 or 2.31 m/s^2 (rounded to two decimal places).

The best choice is A.

A Cessna Aircraft Has a Lift-Off Speed of 120 Km/hr