A rock is thrown straight up with an initial velocity of 19.6 m/s.What time interval elapses between the rock's being thrown and its return to the original launch point? (Acceleration due to gravity is 9.80 m/s². ) A)4.00 s B)5.00 s C)8.00 s D)10.0 s

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Quizplus · Accepted Answer

The time to reach the highest point is given by t = v/g = 19.6 m/s / 9.8 m/s² = 2 s. The total time for the round trip is twice this, so 2 * 2 s = 4 s.

A Rock Is Thrown Straight Up with an Initial Velocity