Starting from rest,a car accelerates down a straight road with constant acceleration a for a time t,then the direction of the acceleration is reversed, (i.e. ,it is −a),and the car comes to a stop in an additional time t,the time for the whole trip being 2t.At what time,or times,is the average velocity of the car for the trip equal to its instantaneous velocity during the trip?
A)There is no such time.
B)It is at the halfway point at t.
C)This occurs at 2 times,0.5t and 1.5t.
D)This occurs at 2 times,0.707t and 1.293t.

Question

Quizplus · Accepted Answer

The average velocity of the car for the trip is equal to its instantaneous velocity at the points where the car has covered half of the total distance in each segment of the trip, which occurs at 0.5t and 1.5t.

Starting from Rest,a Car Accelerates Down a Straight Road with Constant