A deuteron,with the same charge but twice the mass of a proton,moves with a speed of 3.0 ´ 10⁵m/s perpendicular to a uniform magnetic field of 0.20 T.Which of the paths described below would it follow? (q_p = 1.6 x 10^-19 C and m_d = 3.34 x 10^-27 kg)

Question

Quizplus · Accepted Answer

The formula for the radius of the circular path of a charged particle in a magnetic field is:
r = mv / (qB)
where r is the radius of the circular path, m is the mass of the particle, v is its velocity, q is its charge, and B is the magnetic field strength.
Substituting the values given:
r = (2 * m * v) / (q * B)
r = (2 * 3.34 x 10^-27 kg * 3.0 x 10^5 m/s) / (1.6 x 10^-19 C * 0.20 T)
r = 3.1 cm
Therefore, the deuteron would follow a circular path with a radius of 3.1 cm. Choice C is the correct answer.

A Deuteron,with the Same Charge but Twice the Mass of a Proton,moves