An electron is moving at a speed of 6.0 x 106 m/s at an angle of 30 with respect to a uniform magnetic field of 8.0 x 10-4 T.What is the radius of the resulting helical path? (me = 9.11 x 10-31 kg,qe = 1.6 x 10-19 C)
A) 8.5 cm
B) 4.3 cm
C) 3.7 cm
D) 2.1 cm
Correct Answer:
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