Two parallel conductors each of 0.50 m length,separated by 5.0 x 10^-3 m and carrying 3.0 A in opposite directions,will experience what type and magnitude of mutual force? (magnetic permeability in empty space µ₀ = 4p x 10^-7 TF*m/A)

Question

Quizplus · Accepted Answer

The formula for the magnetic force between two parallel conductors carrying current in opposite directions is:

F = μ0*I1*I2*L/(2*pi*d)

where F is the force, μ0 is the magnetic permeability of free space, I1 and I2 are the current in the conductors, L is the length of the conductors, and d is the distance between the conductors.

Plugging in the given values, we get:

F = (4*pi*10^-7)*(3 A)*(3 A)*(0.5 m)/(2*pi*5*10^-3 m)
  = 1.8*10^-4 N

The force is repulsive because the two currents are in opposite directions. Therefore, the correct answer is (D) repulsive, 1.8 x 10^-4 N.

Two Parallel Conductors Each of 0