A metal wire has a resistance of 25.00 W under room temperature conditions of 25 $\degree$C.When the wire is heated to 85 $\degree$C the resistance increases by 0.75 W.What is the temperature coefficient of resistivity of this metal? A)5.0 x 10^-4 ( $\degree$C)^-1 B)1.3 x 10^-3 ( $\degree$C)^-1 C)1.5 x 10^-3 ( $\degree$C)^-¹ D)2.5 x 10^-3 ( $\degree$C)^-1

Question

Quizplus · Accepted Answer

The temperature coefficient of resistivity (α) can be calculated using the formula: α = (ΔR / (R₀ * ΔT)), where ΔR is the change in resistance (0.75 Ω), R₀ is the initial resistance (25.00 Ω), and ΔT is the change in temperature (85°C - 25°C = 60°C). Substituting these values gives α = (0.75 / (25 * 60)) = 5.0 x 10^-4 (°C)^-1.

A Metal Wire Has a Resistance of 25 °\degree° CWhen the Wire Is Heated to 85

A Metal Wire Has a Resistance of 25 $\degree$ CWhen the Wire Is Heated to 85