A resistor is connected to a battery with negligible internal resistance.If you replace the resistor with one that has twice the resistance,by what factor does the power dissipated in the circuit change?
A)0.50
B)0.25
C)4.0
D)2.0

Question

Quizplus · Accepted Answer

The power dissipated in a resistor is given by P = V^2/R. If the resistance is doubled, the power becomes P' = V^2/(2R) = (1/2)(V^2/R) = 0.5P. Thus, the power is halved, so the factor is 0.50.

A Resistor Is Connected to a Battery with Negligible Internal