A proton (+1.6 x 10^-19 C)moves 10 cm on a path in the direction of a uniform electric field of strength 3.0 N/C.How much work is done on the proton by the electrical field? A)4.8 x 10^-20 J B)-4.8 x 10^-20 J C)1.6 x 10^-20 J D)zero

Question

Quizplus · Accepted Answer

The work done by an electric field on a charge is given by W = qEd, where q is the charge, E is the electric field strength, and d is the distance moved in the direction of the field. Substituting the given values: W = (1.6 x 10^-19 C)(3.0 N/C)(0.1 m) = 4.8 x 10^-20 J.

A Proton (+1