A 9.0-V battery is connected between two parallel metal plates 4.0 mm apart.What is the magnitude of the electric field between the plates? A)2.3 x 10³ N/C B)9.0 N/C C)2.3 N/C D)0.75 x 10^-6 N/C

Question

Quizplus · Accepted Answer

The electric field between two parallel conducting plates can be calculated using the formula:

E = V/d

where E is the electric field, V is the potential difference between the plates, and d is the distance between the plates.

In this case, the potential difference is given as 9.0 V and the distance between the plates is 4.0 mm = 0.004 m. Therefore,

E = 9.0 V / 0.004 m = 2.25 x 10^6 N/C

However, this is only the magnitude of the electric field. Since the plates are parallel and the electric field is uniform between them, the direction of the electric field is from the positive plate to the negative plate. Therefore, we need to include the negative sign to indicate the direction of the field. The answer is thus:

E = -2.3 x 10^6 N/C

Note that this is not one of the answer choices given, but the closest choice is A) 2.3 x 10^6 N/C.

A 90-V Battery Is Connected Between Two Parallel Metal Plates 4