In an isobaric process 4.5 x 10⁴ J of work is done on a quantity of gas while its volume changes from 2.6 m³ to 1.1 m³.What is the pressure during this process?

Question

Quizplus · Accepted Answer

In an isobaric process, the pressure is constant. Therefore, we can use the formula:

W = PΔV

where W is the work done on the gas, P is the pressure, and ΔV is the change in volume.

Plugging in the values given, we get:

4.5 x 10^14 J = P[(1.1 m^3) - (2.6 m^3)]

Solving for P, we get:

P = 3.0 x 10^14 Pa

Therefore, the correct answer is C.

In an Isobaric Process 4