Three resistors, 80 Ω, 10 Ω, and 70 Ω, are wired in parallel and connected to a 120-V battery. How much current flows in this circuit?

Question

Quizplus · Accepted Answer

When resistors are connected in parallel, the total resistance ($R_{total}$) can be calculated using the formula $\frac{1}{R_{total}} = \frac{1}{R_1} + \frac{1}{R_2} + \frac{1}{R_3}$. For resistors of 80 Ω, 10 Ω, and 70 Ω, the total resistance is $\frac{1}{R_{total}} = \frac{1}{80} + \frac{1}{10} + \frac{1}{70}$, which simplifies to $R_{total} = 8 \Omega$. Using Ohm's Law ($V = IR$), the total current ($I$) can be calculated as $I = \frac{V}{R_{total}} = \frac{120V}{8\Omega} = 15A$.

Three Resistors, 80 Ω, 10 Ω, and 70 Ω, Are