Cystic fibrosis is a genetic disorder in humans where the person has two homozygous recessive alleles for the gene. If the disease is left untreated, it causes severe health problems in the individual. If 9 in 10,000 newborn babies have the disease, what are the expected frequencies of the dominant (A1) and recessive (A2) alleles according to the Hardy-Weinberg equation?
A) f(A1) = 0.9997, f(A2) = 0.0003
B) f(A1) = 0.9800, f(A2) = 0.0200
C) f(A1) = 0.9700, f(A2) = 0.0300
D) f(A1) = 0.9604, f(A2) = 0.0392
Correct Answer:
Verified
Q10: A species of moth lays eggs on
Q11: Researchers studying a small milkweed population note
Q12: Which of the following statements best explains
Q13: Researchers studying a small milkweed population note
Q14: Which one of the following conditions would
Q16: Harmful mutations occur in both diploid and
Q17: Which of the following statements is accurate
Q18: The higher the proportion of loci that
Q19: Which of the following situations leads to
Q20: Which of the following comparisons illustrates differences
Unlock this Answer For Free Now!
View this answer and more for free by performing one of the following actions
Scan the QR code to install the App and get 2 free unlocks
Unlock quizzes for free by uploading documents