In a cross of individuals who both possess this genotype, AaBbCc, what proportion of the offspring is predicted to have the genotype, AABBCC?
A) 1/4
B) 1/8
C) 1/16
D) 1/64

Question

Quizplus · Accepted Answer

Each gene pair (Aa, Bb, Cc) segregates independently, and the probability of obtaining the homozygous dominant genotype (AA, BB, CC) for each pair is 1/4. Therefore, the combined probability for AABBCC is (1/4)^3 = 1/64.

In a Cross of Individuals Who Both Possess This Genotype