By considering the parallel plate capacitor that is being charged, show that the "displacement current"-defined as å₀ times the first integral on the right-hand side of the last equation in Eq. [20.24]-is equal to the "conduction current," I, in the same equation.

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The Answer of By considering the parallel plate capacitor that is being charged, show that the "displacement current"-defined as å₀ times the first integral on the right-hand side of the last equation in Eq. [20.24]-is equal to the "conduction current," I, in the same equation.

By Considering the Parallel Plate Capacitor That Is Being Charged