What is the resistance of a tube of mercury of length 1.0 m and diameter 1.0 mm?
A)1.3 Ù
B)1.6 Ù
C)3.2 Ù
D)5.2 Ù

Question

Quizplus · Accepted Answer

The resistance $R$ of a conductor (in this case, a tube of mercury) can be calculated using the formula $R = \rho \frac{L}{A}$, where $\rho$ is the resistivity of the material, $L$ is the length of the conductor, and $A$ is the cross-sectional area. For mercury, $\rho$ is approximately $94 \times 10^{-8} \Omega \cdot m$. The length $L$ is given as 1.0 m, and the diameter of the tube is 1.0 mm, which means the radius $r$ is 0.5 mm or $0.5 \times 10^{-3} m$. The cross-sectional area $A$ of the tube is $\pi r^2$, which calculates to $\pi \times (0.5 \times 10^{-3})^2 m^2$. Plugging these values into the resistance formula gives a resistance close to 1.3 $\Omega$, making option A the correct choice.

What Is the Resistance of a Tube of Mercury of Length