A uniform electric field of magnitude 150 V/m is directed in the positive x-direction. A +12.0 ìC charge moves from the origin to the point (x, y) = (20.0 cm, 25.0 cm). Through what potential difference does the charge move?

Question

Quizplus · Accepted Answer

The potential difference is calculated using the formula ΔV = -E * Δx, where E is the electric field and Δx is the displacement in the x-direction. Here, Δx = 0.2 m, so ΔV = -150 V/m * 0.2 m = -30 V. The work done is W = q * ΔV = 12.0 μC * 30 V = 3.6 × 10^-4 J.

A Uniform Electric Field of Magnitude 150 V/m Is Directed