Figure 15.2
The figure shows pressure nodes in a tube that is open on both ends.
-For the wave in Fig. 15.2, what is the fundamental frequency if the distance between two pressure nodes is 30 cm? The speed of sound in air is 343 m/s.
A)f = 190.6 Hz
B)f = 381.1 Hz
C)f = 571.7 Hz
D)f = 1143.3 Hz

Question

Figure 15.2
The figure shows pressure nodes in a tube that is open on both ends. 
-For the wave in Fig. 15.2, what is the fundamental frequency if the distance between two pressure nodes is 30 cm? The speed of sound in air is 343 m/s.
A)f = 190.6 Hz 
B)f = 381.1 Hz 
C)f = 571.7 Hz 
D)f = 1143.3 Hz

Quizplus · Accepted Answer

The fundamental frequency is the lowest frequency at which a wave can propagate. For a wave in air, the fundamental frequency is given by:$$f = v/\lambda$$where:* f is the frequency in Hz* v is the speed of sound in m/s* λ is the wavelength in mIn this case, the distance between two pressure nodes is 30 cm, which is half of the wavelength. Therefore, the wavelength is 60 cm, or 0.6 m. The speed of sound in air is 343 m/s. Substituting these values into the equation above, we get:$$f = 343 m/s / 0.6 m = 571.7 Hz$$Therefore, the fundamental frequency is 571.7 Hz.

Figure 15.2 The Figure Shows Pressure Nodes in a Tube That Is