Corn syrup flows through a tube with a radius of 2 cm and a length of 2 m, at a speed of 0.4 m/s. What is the pressure difference in the tube? (Viscosity of syrup is ç = 1.38 Pa s.) A)22 kPa B)2.2 Pa C)2.2 × 10^-2 Pa D)8.8 × 10^-4 Pa

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Quizplus · Accepted Answer

The pressure difference in the tube can be calculated using Poiseuille's law, which is given by $\Delta P = \frac{8 \mu L v}{\pi r^4}$, where $\Delta P$ is the pressure difference, $\mu$ is the viscosity of the fluid, $L$ is the length of the tube, $v$ is the speed of the fluid, and $r$ is the radius of the tube. Substituting the given values: $\Delta P = \frac{8 \times 1.38 \times 2 \times 0.4}{\pi \times (0.02)^4}$, we find that the pressure difference is approximately 22 kPa.

Corn Syrup Flows Through a Tube with a Radius of 2