Solve the inequality.
-$$10 \geq \frac { 5 x + 2 } { 3 } \geq - 5$$
A) $x \geq - \frac { 17 } { 5 }$
B) $x \leq \frac { 28 } { 5 }$
C) $- \frac { 17 } { 5 }

Question

Solve the inequality.
-$$10 \geq \frac { 5 x + 2 } { 3 } \geq - 5$$
A) $x \geq - \frac { 17 } { 5 }$
B) $x \leq \frac { 28 } { 5 }$
C) $- \frac { 17 } { 5 } < x < \frac { 28 } { 5 }$
D) $- \frac { 17 } { 5 } \leq x \leq \frac { 28 } { 5 }$

Quizplus · Accepted Answer

To solve the inequality $10 \geq \frac { 5 x + 2 } { 3 } \geq - 5$, we multiply all parts by 3 to eliminate the denominator, resulting in $30 \geq 5x + 2 \geq -15$. Solving each part separately for $x$, we get $x \leq \frac{28}{5}$ and $x \geq -\frac{17}{5}$, which combined gives $- \frac { 17 } { 5 } \leq x \leq \frac { 28 } { 5 }$.

Solve the Inequality 10≥5x+23≥−510 \geq \frac { 5 x + 2 } { 3 } \geq - 510≥35x+2​≥−5

Solve the Inequality $10 \geq \frac { 5 x + 2 } { 3 } \geq - 5$