Solve by completing the square.
-$$x ^ { 2 } + 4 x - 3 = 0$$
A) $\frac { - 4 \pm 2 \sqrt { 7 } } { 2 }$
B) $\frac { - 4 - 2 \sqrt { 7 } } { 2 }$
C) $\frac { 4 + 2 \sqrt { 7 } } { 2 }$
D) $- 4 \pm 2 \sqrt { 7 }$

Question

Quizplus · Accepted Answer

To solve the equation $x^2 + 4x - 3 = 0$ by completing the square, first move the constant term to the right side: $x^2 + 4x = 3$. Then, add $(\frac{4}{2})^2 = 4$ to both sides to complete the square: $x^2 + 4x + 4 = 7$. This gives $(x + 2)^2 = 7$, so $x + 2 = \pm \sqrt{7}$. Solving for $x$ gives $x = -2 \pm \sqrt{7}$, which simplifies to $\frac{-4 \pm 2\sqrt{7}}{2}$.

Solve by Completing the Square x2+4x−3=0x ^ { 2 } + 4 x - 3 = 0x2+4x−3=0

Solve by Completing the Square $x ^ { 2 } + 4 x - 3 = 0$