Find the Sum $$\sum _ { k = 1 } ^ { n } \left( k ^ { 2 } + 5 \right)$$

Find the sum.
- $$\sum _ { k = 1 } ^ { n } \left( k ^ { 2 } + 5 \right)$$

A) $\frac { n ( n + 1 ) ( 2 n + 1 ) + 30 n } { 6 }$
B) $\frac { n ( n + 1 ) ( 2 n + 1 ) + 6 n } { 6 }$
C) $\frac { n ( n + 1 ) ( 2 n + 1 ) + 30 } { 6 }$
D) $\frac { n ( n + 1 ) ( 2 n + 1 ) } { 6 }$