A three-phase wye-connected load is connected to a 480 V three-phase line. The line current is 36 A. If this load is purely resistive, what is the total amount of power being used in this circuit?
A) 51.84 kW
B) 29.93 kW
C) 7.48 kW
D) 12.96 kW

Question

Quizplus · Accepted Answer

The total power used in a purely resistive three-phase wye-connected load is given by P = √3 × Vph × Iph × cos(θ), where Vph is the phase voltage and Iph is the phase current. Since the load is wye-connected, the phase voltage is equal to the line voltage, which is 480 V. The power factor of a purely resistive load is cos(θ) = 1. Therefore, the total power used is P = √3 × 480 V × 36 A × 1 = 29.93 kW.

A Three-Phase Wye-Connected Load Is Connected to a 480 V