If a quasar has a recessional velocity of 2.7*10⁵ km/s and is determined to be 3600 Mpc, what is the Hubble constant based on this quasar alone? Hint: Not that the units of your result should be (km/s)/Mpc to see what arithmetic process you need to perform. A) 50 km/s/Mpc B) 9.7*10⁸ (km/s)Mpc C) 75 km/s/Mpc D) 0.013 km/s/Mpc E) 273,600 km/s/Mpc

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Quizplus · Accepted Answer

The Hubble constant (H₀) is calculated using the formula H₀ = velocity/distance. Here, H₀ = (2.7*10⁵ km/s) / (3600 Mpc) = 75 km/s/Mpc.

If a Quasar Has a Recessional Velocity of 2